Re: Hg needed for fusion?
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Re: Hg needed for fusion?         


Author: Sam Wormley
Date: Jun 8, 2008 15:24

The Moron wrote:
> Sam Wormley wrote:
>> The Moron wrote:
>>
>>> I don't know. Hg is heavier than Fe, so if one keeps dumping Hg onto
>>> the sphere, it will either undergo total gravitational collapse or a
>>> very violent supernova runaway explosion.
>> No... not a supernova explosion.... but 3 solar mass sphere of Hg
>> should collapse into a black hole. But don't stick your finger in
>> there, because you ain't getting it back.
>
> So, based on Sam's response, let's see what we get:
>
> 3*M_0 ~ 2*10^30 kg
>
> d_{Hg} ~ 13.5 g/cm^3, hence, we can solve the following for r in cm:
>
> 13.5 g/cm^3 = 3*M_0*10^3 g/(4/3*Pi*r^3)/cm^3. Solving with Maple, I get:
>
> r ~ 473,416 km. ...
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Re: Hg needed for fusion?         


Author: The Moron
Date: Jun 8, 2008 15:49

Sam Wormley wrote:
> The Moron wrote:
>> Sam Wormley wrote:
>>> The Moron wrote:
>>>
>>>> I don't know. Hg is heavier than Fe, so if one keeps dumping Hg
>>>> onto the sphere, it will either undergo total gravitational
>>>> collapse or a very violent supernova runaway explosion.
>>> No... not a supernova explosion.... but 3 solar mass sphere of Hg
>>> should collapse into a black hole. But don't stick your finger in
>>> there, because you ain't getting it back.
>>
>> So, based on Sam's response, let's see what we get:
>>
>> 3*M_0 ~ 2*10^30 kg
>>
>> d_{Hg} ~ 13.5 g/cm^3, hence, we can solve the following for r in cm:
>>
>> 13.5 g/cm^3 = 3*M_0*10^3 g/(4/3*Pi*r^3)/cm^3. Solving with Maple, I
>> get: ...
Show full article (1.31Kb)
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