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  Re: Basic Geometry for Blind Poe         


Author: Peter Webb
Date: Dec 11, 2006 17:51

Remember, what you trying to teach me is a universal physical and
mathematical LAW of 1/r^2. I say it doesn't apply to dish antennae.

**** It does apply to dish antenna once you get far enough away. Far enough
away is

r >> d^2/w

Where d = aperture and w = wavelength.

There is nothing at all unusual about this; all non-point sources have
similar rules. The light from a flurescent light is not 4 times as strong 1
mm from the surface as it is 2 mm from the surface; the light flux is almost
exactly the same. A flourescent tube does not display an iverse square law
unless
r>>l

Where l is the length of the tube.
2 Comments
  Re: AXIOM.         


Author: John Jones
Date: Dec 11, 2006 11:58

R. Srinivasan wrote:
> On Dec 11, 3:54 am, "John Jones" aol.com> wrote:
>> 1) The axioms that mathematics chooses for its discourse will always be
>> employed for contingent reasons, these arising from a mathematicians...
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  Re: What is the model for this information         


Author: John Jones
Date: Dec 11, 2006 11:48

Konrad Viltersten wrote:
> I'm afraid i don't get your point. Was it ment as a correction
> to the previous poster? Elaboration? What is "urinary"?
> According to Oxford dictionary it is something in connection
> with urine and i hardly think that's the point. A typo?

I exhibit no typo's. Let me re-phrase. The urinary member is present
with a 0.5 probability in the general population, for which the
addition of the remaining urinary structure comprises a probability of
1.
no comments
  Re: Proving "a OR !a"         


Author: Jan Burse
Date: Dec 11, 2006 11:38

Konrad Viltersten wrote:
>> It needs double negation elimination and RAA twice....
>> (first twice RAA then DNE)
>> Hope this doesn't give it away to much..
>
>
> No, it really doesn't. :)
> What i've got this far is the following.
>
> Assuming
> 1) ! (a || !a)
> 2) (a || !a)
> i can eliminate the implication and obtain falsity. From there,
> by RAA, i can either conclude NOT (1) as well as NOT (2).
>
> So, there i am, having concluded (1) and (2) from, well, the
> assumptions of (1) and (2). Waste of pencil this far, hehe.
>
> More hints!
> ...
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  Proving "a OR !a"         


Author: Konrad Viltersten
Date: Dec 11, 2006 04:27

How can one show that the following is a tautology by means of
natural deduction?

(a) OR (NOT a)

I've tried to use the truity and different approaches with
eliminations and introductions but i can't make it work. If
it's possible, i'd prefer a hint before a spoiling straight
forward answer.

--
Vänligen
Konrad
---------------------------------------------------

Sleep - thing used by ineffective people
as a substitute for coffee

Ambition - a poor excuse for not having
enough sence to be lazy
---------------------------------------------------
2 Comments
  How to prove (Ax)(Fx & Gx) <--> ~(Ex) (Fx -> ~Gx) ?         


Author: translogi
Date: Dec 11, 2006 04:24

Hello,
,
Does anybody knows how to prove
(Ax)(Fx & Gx) <--> ~(Ex) (Fx -> ~Gx)

using only primitive natural deduction rules?

from left to right
(Ax)(Fx & Gx) |- ~(Ex) (Fx -> ~Gx)

i get as far as
1 (1) (Ax)(Fx & Gx) Premisse
2 (2) (Ex)(Fx -> ~Gx) Assumption
3 (3) Fa -> ~Ga 2 ES /Ass
1 (4) Fa & Ga 1 US
1 (5) Fa 1 &E
1 (6) Ga 1 &E
1,3 (7) ~Ga 5,3 MP / ->E
1,3 (8) Ga & ~Ga 6,7 &I
1 (9) ~(Ex)(Fx -> ~Gx)1,2-8 RAA ??????

but I am not sure if RAA is used here according to the rules
maybe only ~(Fa -> ~Ga) is derivable here so i got stuck there
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