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  "compress time"         


Author: RichD
Date: May 15, 2008 20:42

I attended a lecture recently on quantum computers,
for solving NP problems. Of course, the speaker
assumes P /= NP, for classical machines.

He remarked "if P = NP, we could compress time".

What does that mean? I didn't get the chance to
ask him.

--
Rich
1 Comment
  I'm dying to get into that car.         


Author: Anonymous Sender
Date: May 15, 2008 19:28

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no comments
  Theories that prove their own consistency         


Author: Gc
Date: May 15, 2008 16:15

Hi,

I have an impression that certain first order theories where the
recursive definition of integer multiplication is weakened can prove
their own consistency, so the diagonalization doesn`t go trough but
the consistency predicate is formalizable. I would like to know more,
references/ explanations anybody?
2 Comments
  Theorem II.8.10 (SOSOA): maybe interesting result, probably wrong proof         


Author: Jan Burse
Date: May 15, 2008 12:06

I have serious doubt about the following theorem:
Theorem II.8.10 (strong soundness theorem). The following
is provable in RCA_0. If there exists a weak countable
model of X subset Snt, then X is consistent.

The doubt concerns the proof of the above theorem. The proof
goes along the following lines:

If X were inconsistent, then there were a proof of
~(s1 & .. & sn), with s1 .. sn in X. Ok, no doubt.

We can assume that we have a cut free proof
of this. Ok, no doubt.

Let M be a weak countable model of X, then we
have for the subformulas s in the proof M(s)=1.
**No, thats not true, big doubt on this.**

Because M(s1)=..=M(sn)=1, and M(~(s1 &..& sn))=1,
we arrive at a contradiction.

My doubt is based on a simple observation how typically
cut free proofs work on propositional formulas(*):
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1 Comment
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