Is there anything wrong with:

if ( defined $one && defined $two && $one eq $two ) {
#### do something
}

On Tue, May 6, 2008 at 9:49 AM, Robert Hicks gmail.com> wrote:

No. Its fine.
You might be interested in "Operator Precedence and Associativity" [1]

[1] http://perldoc.perl.org/perlop.html#Operator-Precedence-and-Associativity

From: Robert Hicks gmail.com>

As far as I can tell not. I was afraid the operator precedence might
play tricks with it, but looks like it doesn't:

V:\>perl -MO=Deparse -e "defined $one && defined $two && $one eq
$two"
$one eq $two if defined $one and defined $two;
-e syntax OK

V:\>perl -MO=Deparse -e "if(defined $one && defined $two && $one eq
$two) {print 'aha'}"
if (defined $one and defined $two and $one eq $two) {
print 'aha';
}
-e syntax OK

I would write it as

Jenda Krynicky wrote:

On Tue, 06 May 2008 18:04:00 +0200, Jenda Krynicky wrote:

A bit more explicitly (and interestingly different):

$ perl -MO=Deparse,-p -e 'defined $one && defined $two && $one eq $two'
((defined($one) and defined($two)) and ($one eq $two));
-e syntax OK