159: static PartsList GlobalPartsList;
160: };
161:
162: PartsList PartsList::GlobalPartsList;

I would understand if it initialized the object
GlobalPartsList with some value, but as it is now, it seems to me
without purpose.

Thanks,

Rafael

Rafael Anschau wrote:

It _defines_ the static data member. Read up on static data members.

V

Yes, my text says it initializes or defines it there. That line 159
only declares it.
But initializes it, defines it with what ? What it does is to make it
possible to later assign
a value ?

[]´s

Rafael

Thanks, but same question.

int foo::bar = 42;//OK, =42
int foo::bar; //??

[]´s

Rafael

Thanks but same question:

int foo::bar = 42; //Ok, =42
int foo::bar;// ?? =??

[]´s

Rafael

Rafael Anschau wrote:

If your question is what value 'foo::bar' gets, the answer is 0.

On May 9, 8:43 am, Rafael Anschau gmail.com> wrote:

When an object is initialised it calls the objects constructor.
So line 162 creates the object and calls the objects constructor (see
constructor for PartsList). Once it has been constructed you can now
call all the public methods available in PartsList.

PartsList::GlobalPartsList.doSomthing()

Thank you now I get it. The purpose is to make members avalible
and run the constructor. Great.

[]´s

Rafael

That´s an old 80´s 90´s (70´s ?) electronic compliment.

[]´s

Rafael