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Is there a way to do the following code so that
day_data and other_data_1 occupy the same byte in
memory? Using the debugger, the addresses I'm getting are:
12ff5c - myVar.day_data
12ff60 - myVar.other_data_1
I'm using Microsoft Visual C++. sizeof(unsigned short) returns 2.
Thanks!
oiccicny@twcny.rr.com

how can a song or a video can be played in c++.

Hi,
I'm trying to read some binary data from a file, I've read a few bytes
of the data into a
char array with ifstream. Now I know that the first 4 bytes in the
char array represent
an integer. How do I go about converting the elements to an integer?
regards, Igor

Hey Jon,

Where should I go after Logging in to the google website? Do I go to
a specific link and read the Wiki blogs?

Suppose I have a text file with the input:
1 2 3 4 5 6 7 8 9 10 ! Comment: Integers 1 - 10

How do I write a C++ program that reads in this line into a 10-element
vector and ignores the comment?

Thanks.

That's great, but do we really know what we do? Once someone found a
new type “diet” his is trying to use it for his business, but it is a
wrong approach. Your business is different, there are departments,
such as Sales, HR, Security, Financial. These departments function in
a different ways and if you will apply the same information diet to
all of them you will fail.

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The code is simple:

// Token.h
#ifndef TOKEN_H
#define TOKEN_H

#include
#include

Hello,

I have some cuestions about constness with standard containers and
pointers.
Supose I have a list of pointers to some class B:

std::list< B * > > list;

I have readed that constness in std::list is the same that it is in C
arrays (const std::list makes const both the list and its content):

const std::list< B * > > constList;

I can't do:

constList->push_back(x);

But, is it still possible to call any non-const member funcion of B?:

void B::nonConstMemberFuncion();

As in:

constList.begin()->nonConstMemberFuncion();

a) It is possible. I don't want the user to add elements nor modify
any of the list. Which is the correct way of doing this?

const std::list< const B * const > > constList;
const std::list< const B * > constList;