Hi,
My question is how are the outputs same for the two below queries.
First has 'print $0, NF' and the other 'print NF, $0'; 'print NF, $0'
is working as expected but not 'print $0, NF'; Can someone please
explain.

grampian@/export/home/sys1mi/delete_1--->gawk '/N_APPL_SYST_CPNT/
{print $0, NF}' *
4 N_APPL_SYST_CPNT number := 35;
8 from prwmgr.appl_syst_cpnt_run@spartap where
appl_syst_cpnt_id=N_APPL_SYST_CPNT...

Input:

Index of /pub/testenv on test.example.com:21

---

  2008 Sep 18 23:53  File        ftp://test.example.com:21/

pub/testenv/.bash_history">.bash_history  (2885 bytes)

  2008 Sep 03 15:48  Directory   ftp://test.example.com:21/

pub/testenv/.ssh/">.ssh/

  2008 Jun 27 22:40  Directory   ftp://test.example.com:21/

pub/testenv/.subversion/">.subversion/

  2008 Jul 28 18:38  File        ftp://test.example.com:21/

pub/testenv/.viminfo">.viminfo  (5884 bytes)

  2008 Sep 05 18:59  File        ftp://test.example.com:21/

pub/testenv/abcd.0.256.3.tar.gz">ass.0.256.3.tar.gz  (96594844 ...

Hi,

Given 2 files file1 and file2, each with a single field made of rows
like 't010203.txt', does this:

awk 'NR == FNR {r[$0]=$0}; NR != FNR {if (!$0 in r) print $0}' file1 file2

output the lines in file2 that were not present in file1? I'm pretty
sure it does, but was wondering if there's a better way to do it or
whether I'm overlooking something. My main doubt is the use of '!' in
the 'if' statement.

Cheers,

Hi,

A box
B box
xyz(command)
if box A and B responds ok for the xyz command thats fine and if any
one of the box gives not ok response i want to kill one app
process(like pgrep app).

Am newbie in awk, i think using awk would be elegant in this
situtation. Please help me

Regards,
Gokul

In article 34g2000hsh.googlegroups.com>,
gmail.com> wrote:

How is this different from what I said?

On 9/14/2008 4:25 PM, rubin1001@gmail.com wrote:

Hello,

I'm a newbie at awk and I need this for some work. There's a data sheet I
process.

A1 0.65 3
A2 0.33 5
A3 0.55 5
.........

And I hope add a new column at the end and fill up with "matched" words.
So there are 4 columns divided by space. The result should be this.

A1 0.65 3 matched
A2 0.33 5 matched
A3 0.55 5 matched
.................

Thank you very much~

Regards,

Amy

I am a relative novice with awk and am stuck on something I can't help
thinking ought to be really simple. I have a file "mydata.txt" as
below

a 999
b 1000
c 1001
d 1002

I am trying to write a simple script that will output the following
from this file

a 999
b 1000 a 999
c 1001 b 1000
d 1002 c 1001

I just can't seem to do this, but it must be really simple, no?

Thanks

Hi,

What does the POSIX Standard for awk say about coercion as described on
pages 44-45 of The Awk Programming Language book (1988, Aho, Weinberger,
Kernighan)?

I.e., "" variable is treated as a string, 0 + variable is treated as a
number.

Thanks.
Bill Seivert

gawk doc error - awk eval error
what was a simple gawk doc error lead to a serious awk
arg evaluation error in awk/gawk but Not in mawk

the 1999 gawk.hlp or latest gawk.html
http://www.weihenstephan.de/~syring/win32/UnxUtilsHlp.zip
http://www.gnu.org/software/gawk/manual/
say in section: 'Calling Built-in Functions'
i=5; j=atan2(i++, i *= 2)
"If the order of evaluation is left to right, then i first becomes
six, and then 12, and atan2 is called with the two arguments
six and 12. But if the order of evaluation is right to left, i first
becomes 10, and then 11, and atan2 is called with the two
arguments 11 and 10."

since i++ yields value of i and then incs i, statement should be:
'called with arguments five and 12' 'or 10 and 10' ???