Re: you have nothing fundamental if you don't accept my lever in your ass
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Re: you have nothing fundamental if you don't accept my lever in your ass         

Group: alt.philosophy · Group Profile
Author: Immortalist
Date: Sep 8, 2008 22:28

On Sep 8, 9:01 pm, dedanoe gmail.com> wrote:
> newton and coulomb are wrong, wrong, wrong!
>

Suppose you are right just for a moment, what kinds of changes to
science would your conclusion entail?
> archimedes' statement "magnitudes are in balance
> on distances reciprocal to their weights" has
> no exceptions. every two weights from same local
> brotherhood and under same father-weight mutually
> interact directly according to archimedes' lever law.
> ==============================================
> the lever law divided with time:
> (F1 D1 = F2 D2)/time <=> F1 V1 = F2 V2 <=>
> (F1, V1) = (0, extreme) <=> (F2, V2) = (extreme, 0)
> it reads: subjected to no force the weight
> preserves its uniform motion but when it hits
> the breaks it exerts respective extreme force.
> ==============================================
> newton II: F = a m should be F = i am i.e.
> (Force is that i am) where "i" evens the units
> left and right. newton/kg cannot be meter/sec^2
> take the lever law for instance F1/D2=F2/D1
> same counterparts left and right or (F1 over F2)
> pure number equals (D1 under D2) pure number.
> by the way, the lever law can be written this way:
> (F1 = kM1 = sD2 and F2 = kM2 = sD2) where k is
> simple analogy proportion making M parallel
> vector with F.
> ==============================================
> the lever law with D = Distance
> F1 D1 = F2 D2 <=> F1 = -F2 iff D1 = -D2
> the law of hydraulics with S = Surface
> F1 S1 = F2 S2 <=> F1 = -F2 iff S1 = -S2
> the law of impacts with V = Volume
> F1 V1 = F2 V2 <=> F1 = -F2 iff V1 = -V2
> ==============================================
> Gravity law compatible with the lever law:
> (F1 = kM1 = sD2 and F2 = kM2 = sD1)
> F1/D2 = F2/D1 = (F1 + F2)/(D1 + D2)
> F1 F2 = k^2 M1 M2 = D1 D2 Sqr((F1 + F2)/(D1 + D2))
> F1/D2 = F2/D1 = Sqrt(k^2(M1/D1)(M2/D2))
> because coulomb's electric law is pure clon-copy
> of newton's gravity for formally same reasons
> with Q = Charge, the electric law must be:
> F1/D2 = F2/D1 = Sqrt(n^2(Q1/D1)(Q2/D2))
>
> prove completed: you have nothing fundamental now
>
> -----<>-----
> / \
> / Infinity \
> / O O \
> | n n |
> | e e |
>>= <=
> | M L |
> | o e |
> \ r s /
> \ e s /
> \ Zero /
> -----==-----
>
> unleash death and tao chaos,
> excellency dedanoe unlishnidaos.http://dedanoe.googlepages.com
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