newton and coulomb are wrong, wrong, wrong!

archimedes' statement "magnitudes are in balance
on distances reciprocal to their weights" has
no exceptions. every two weights from same local
brotherhood and under same father-weight mutually
interact directly according to archimedes' lever law.
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the lever law divided with time:
(F1 D1 = F2 D2)/time <=> F1 V1 = F2 V2 <=>
(F1, V1) = (0, extreme) <=> (F2, V2) = (extreme, 0)
it reads: subjected to no force the weight
preserves its uniform motion but when it hits
the breaks it exerts respective extreme force.
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newton II: F = a m should be F = i am i.e.
(Force is that i am) where "i" evens the units
left and right. newton/kg cannot be meter/sec^2
take the lever law for instance F1/D2=F2/D1
same counterparts left and right or (F1 over F2)
pure number equals (D1 under D2) pure number.
by the way, the lever law can be written this way:
(F1 = kM1 = sD2 and F2 = kM2 = sD2) where k is
simple analogy proportion making M parallel
vector with F.
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the lever law with D = Distance
F1 D1 = F2 D2 <=> F1 = -F2 iff D1 = -D2
the law of hydraulics with S = Surface
F1 S1 = F2 S2 <=> F1 = -F2 iff S1 = -S2
the law of impacts with V = Volume
F1 V1 = F2 V2 <=> F1 = -F2 iff V1 = -V2
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Gravity law compatible with the lever law:
(F1 = kM1 = sD2 and F2 = kM2 = sD1)
F1/D2 = F2/D1 = (F1 + F2)/(D1 + D2)
F1 F2 = k^2 M1 M2 = D1 D2 Sqr((F1 + F2)/(D1 + D2))
F1/D2 = F2/D1 = Sqrt(k^2(M1/D1)(M2/D2))
because coulomb's electric law is pure clon-copy
of newton's gravity for formally same reasons
with Q = Charge, the electric law must be:
F1/D2 = F2/D1 = Sqrt(n^2(Q1/D1)(Q2/D2))

prove completed: you have nothing fundamental now

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