Re: "Mass**" goes to infinity as v approaches c.
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Re: "Mass**" goes to infinity as v approaches c.         

Group: alt.philosophy · Group Profile
Author: Painius
Date: Sep 3, 2008 14:33

"jmfbahciv" wrote in message...
news:7YadnSXy3qQl4CPVnZ2dnUVZ_szinZ2d@rcn.net...
> Jeff▲Relf wrote:
>>
>> You wrote:
>> “ ‘ m = E / c^2 * sqrt( 1 - v^2 / c^2 ) ’
>> So for fixed energy,
>> the mass goes to zero as speed approaches the speed of light. ”.
>> “ Mass** ” goes to infinity as v approaches c:
>> “ Mass = Energy * c^-2 * ( 1 - v^2 / c^2 )^-.5 ”.
>> ** i.e. “ Relativistic Mass ”,
>> not “ Invariant Mass ”, not “ Intrinsic Mass ”, not “ Proper
>> Mass ”.

None of this makes much sense, i'm sorry to say. Are
we forgetting that m = E / c^2 contains "c", not "v", or
IOW the constant "c" is not expected to change? This
formula only shows the amount of change in mass that
results from a given E, energy loss or gain. And in its
more classic form, E = mc^2, it yields the amount of
energy that results from a given loss of mass. "m" in
this formula is actually a delta m, a *change* of mass.

And yes, it *can* be shown using other forms that
mass will indeed tend toward infinity as v tends
toward c.
> Not speed, velocity.

While speed and velocity are interchangeable among
non-physicists, they are different within the realm of
science. Speed is scalar, and velocity is vectorial.
That just means that speed has one value only, the
rate of motion, while velocity is the speed plus the
*direction* of motion.

The speed of electromagnetic radiation, "c", is not a
vectorial quantity in E = mc^2. It is scalar.

Yes, i know this could probably be argued until all our
hairs fall off. So do so if you like. "c" is a scalar speed,
not a vectorial velocity.

happy days and...
starry starry nights!

--
Indelibly yours,
Paine Ellsworth

P.S.: Thank *YOU* for reading!

P.P.S.: http://yummycake.secretsgolden.com
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