| Re: bringin einstein and lorentz to justice |
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Group: alt.philosophy · Group Profile
Author: Dirk Van de moortelDirk Van de moortel Date: Sep 10, 2008 03:20
> Under the leadership of Einstein's SRT:
>
> t'=(t-V/c x/c)/Sqrt(1-Sqr(V/c))
> t=(t'+V/c x'/c)/Sqrt(1-Sqr(V/c))
>
> x'=(x-Vt)/Sqrt(1-Sqr(V/c))
> x=(x'+Vt')/Sqrt(1-Sqr(V/c))
> ---------------------------------
> As cited from "General Physics I"
> SBN: 9989-43006-3
> =================================
> The hack:
> ---------------------------------
> x'/t = (x-Vt)/(t'+V/c x'/c) and
> x/t' = (x'+Vt')/(t-V/c x/c) ==>
> x't'+VSqr(x'/c) = xt-Vt^2 and
> xt-VSqr(x/c)=x't'+Vt'^2 ==>
>
> x't'-xt=-V(Sqr(x'/c)-t^2) and
> x't'-xt=-V(Sqr(x/c)-t'^2) ==>
Typo.
That should be +t^2 and +t'^2
x't'-xt=-V(Sqr(x'/c)+t^2)
x't'-xt=-V(Sqr(x/c)+t'^2)
>
> -(x't'-xt)/V=(t^2+Sqr(x'/c)) and
> -(x't'-xt)/V=(t'^2+Sqr(x/c)) ==>
This is correct again.
>
> t^2+Sqr(x'/c)=t'^2+Sqr(x/c) ==>
Yes, we normally write this as
(x/c)^ - t^2 = (x'/c)^2 - t'^2
It's called the invariance of the interval.
>
> (t-t')(t+t')=(x-x')/c (x+x')/c
sure.
>
> V=x/t=c and V'=x'/t'=c
Where do you get this from?
When you about the coordinates of a light signal sent
out from the origin, you can say, and derive from the
transformation that
if the signal has equation
x/t = c
in the in the unprimed system, then it has equation
x'/t' = c
in the in the primed system.
Do you understand this?
Dirk Vdm
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