Hello, My name is Dymitri.Can you please send the following solution
manual to my e-mail(dymitri.leao@gmail.com)? Your effort will be
greatly appreciated.I am in great need of this.Thank you very much in
advance.

Introduction to Classical Mechanics 2nd edition Atam P Arya

Hi,
I have the axioms of a commutative ring. I want to prove : x.0 =
0.
Basically, assuming.
x+(y+z) = (x+y) +z
x+0=x
x+y=y+x
x+(-x) =0

x.(y.z)=(x.y).z
x.1=x
x.y=y.x

x.(y+z) = x.y + x.z

Given these can I prove x.0=0. I am told I can but am not able to.

Thanks

Hello Buphala!

I need the solution manual from solution manual of Foundations of
Electromagnetic Theory.
Do you have it?

Thanks,

Luciano
berchon@gmail.com

A lot of Solution Manuals in Electronic (PDF)Format!
A lot of Solutions Manuals in Electronic (PDF)Format! Just contact
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Solutions manual list:
Fundamentals of Electric Circuits(3th) By Charles Alexander, Matthew
Sadiku
Introduction to VLSI Circuits and Systems By John P. Uyemura
Linear Algebra with Applications( 6th )edition...

I'm hoping to shorten the arguing phase with the remarkably simple
solution to the factoring problem I've outlined in a previous post by
pointing out a few things:

Given a target composite T, and

z^2 = y^2 + nT

where n is an integer chosen for z to have 3 as a factor--so if T mod
3 = 1 then n=5 will work--then z exists as

z = (f_1 + f_2)/2

when f_1*f_2 = nT, and of course you want integer factors.

The method I have then allows you to find z using a variable I call k,
where

z = 3k/2

and k^2 = 2^{-1} (nT) modulo p

where p is an odd prime less than k as k is an even positive integer.

May seem complicated all in a rush like that but it's incredibly
simple.

Wow. Years of research and then the answer turns out to be incredibly
simple, but that's how it can be with mathematics.

What I like about this method is that there isn't really any room for
people to argue with me about whether or not it solves the factoring
problem (I've posted it in another thread), and it has to be
incredibly fast, as easily shown by mathematical proof.

So no dumb arguments about me having to demonstrate as I haven't
gotten around to testing it yet, at all, as I've just relied on
mathematical proof and it's so simple.

It boggles the mind how simple it is.

Needless to say this research result gives FULL VALIDATION to my
research across the board and will usher in a new era in mathematics
as a discipline around the world.

That brings forward the correct prime counting function, the correct
information about randomness and primes, so that the Goldbach
Conjecture is handled and the Twin Primes conjecture is handled, and
the Riemann Hypothesis can probably be quickly handled.

If you have a target composite T, and use

z^2 = y^2 + nT

where n is used to force z to be divisible by 3, then there will be an
integer k such that

z = 3k/2.

But now find an integer x and odd prime p such that

x^2 = y^2 mod p

where also

2x = k.

So given k as defined before, you find an x that equals one half of
it, and consider a prime p where

(k/2)^2 = y2 mod p.

Then it's trivial to show that

k^2 = 2^{-1}(nT) mod p

and, if f_1*f_2 = nT, then

f_1 = k mod p

and

f_2 = 2k mod p.

Hi there,
I'm interested on the solutions for the following book:
Supply Chain Management, 3/E
author Sunil Chopra
Peter Meindl

Can you provide Instructor's Solutions Manual by mail?

Hi there,
I'm interested on the solutions for the following book:
Supply Chain Management, 3/E
author Sunil Chopra
Peter Meindl

Can you provide Instructor's Solutions Manual by mail?

thanks

Hi

I need solution manual of "foundations of Electromagnetic Theory"

Thank You