...Rothstein (MVP - VB)" <rick.newsNO.SPAM@NO.SPAMverizon.net> wrote in message news:%%23LB7Ss0zIHA.3884@TK2MSFTNGP05.phx.gbl... What if you select the entire column (or columns) containing them and then Edit/ReplaceAll the comma with a dot? Rick "Jim" <jim6651@nospamTRTnet.nl> wrote in message news:485572aa$0$6000$9a622dc7@news.kpnplanet.nl... I know, and thanks, but I...

What if you select the entire column (or columns) containing them and then Edit/ReplaceAll the comma with a dot? Rick "Jim" <jim6651@nospamTRTnet.nl> wrote in message news:485572aa$0$6000$9a622dc7@news.kpnplanet.nl... I know, and thanks, but I don't want to cahnge the regional settings. I have imported a file with financial data and I have somehow to convert this from comma ...

... functions without special attributes like HoldFirst,.. are evaluated before beeing fed to the function. Therefore, RandomReal[GammaDistribution[L, 1/L], 2] is evaluated before beeing fed to ReplaceAll. You may prevent this by wrapping it into Hold or HoldForm. Hope this helps, Daniel Mac wrote: Can somebody explain why the following replacement rule works ...

... to use word basic commands to edit out the mu's but I do not seem to be able to get this to work. I have used commands such as put '[EditReplace.Find="mu",.Replace=" ",.Direction=0,.ReplaceAll,.Wrap=0]' ; but the mu's are not disappearing. Does anyone have any insight in how to get Word to understand what I am trying to do? An alternative would be to issue a Wordbasic command that ...

... if the following will apply straightforwardly to your bigger expressions, but you could use a list of rules with the *ReplaceRepeated[]* operator (short cut //. double-forward slash and period, though in your example *ReplaceAll[]* is enough) or compute a *GroebnerBasis[]* for the variables t1, t2, t3, and eliminating a, b, and c. For instance, In[1]:= {a - b, b - c, c...

... sure if the following will apply straightforwardly to your bigger expressions, but you could use a list of rules with the *ReplaceRepeated[]* operator (short cut //. double-forward slash and period, though in your example *ReplaceAll[]* is enough) or compute a *GroebnerBasis[]* for the variables t1, t2, t3, and eliminating a, b, and c. For instance, In[1]:= {a - b, b - c, c -...

... not sure if the following will apply straightforwardly to your bigger expressions, but you could use a list of rules with the *ReplaceRepeated[]* operator (short cut //. double-forward slash and period, though in your example *ReplaceAll[]* is enough) or compute a *GroebnerBasis[]* for the variables t1, t2, t3, and eliminating a, b, and c. For instance, In[1]:= {a - b, b - c, c - a} ...

...0. b2)) a2+0. c2,0.104632+(-1.+2.71828^(0.195816 b2)) a2+0.195816 c2,<<8>>,<<92>>} is not a list of real numbers with dimensions {102} at {a,b,c} = {0.0369002,0.32,0.158379}. NonlinearRegress::fitfail: The fitting algorithm failed. ReplaceAll::reps: "{msoln} is neither a list of replacement rules nor a valid dispatch table, and so cannot be used for replacing." Thank you for the help!

...( HANDLE hModule, DWORD ul_reason_for_call, LPVOID lpReserved ) { return TRUE; } _declspec (dllexport) void _stdcall Replaceall(string &str, const string &find_what, const string &replace_with) { string::size_type pos=0; while((pos=...

... DllMain( HANDLE hModule, DWORD ul_reason_for_call, LPVOID lpReserved ) { return TRUE; } _declspec (dllexport) void _stdcall Replaceall(string &str, const string &find_what, const string &replace_with) { string::size_type pos=0; while((pos=str.find(...