On Jul 19, 12:05 am, "Mark T.B. Carroll" <Mark.Carr...@Aetion.com> wrote: ssecorp <circularf...@gmail.com> writes: classify ok spam test = spamCount div (spamCount + okCount) (snip)     Couldn't match expected type `(a -> a -> a) -> Int -> t'            against inferred type `Int' (snip) div is a prefix operator because it's letters, not a symbol. To make it infix

classify ok spam test = spamCount div (spamCount + okCount) where okCount = xInY (xmost ok 50) (words test) spamCount = xInY (xmost spam 50) (words test) Couldn't match expected type `(a -> a -> a) -> Int -> t' against inferred type `Int' In the expression: spamCount div (spamCount + okCount) In the definition of `classify': classify