Gulcin
  Home FAQ Contact Sign in
 
Advanced search
MATCHING GROUPS



more...
POPULAR GROUPS

more...

found 18 articles for 0.302 sec
III. SATINALMA ve TEDARIK ZINCIRI YONETIMI ZIRVESI 10 - 11 - 12 Ekim 2008 / Sheraton Istanbul Otel w w w b o s p h o r u s c o n f e r e n c e s c o m / tel: 0-216 486 3O 95 Konusmacilar: (Sunum Sirasiyla) Mehmet Ali NEYZI (Zorlu Enerji Grubu Baskan Yardimcisi), Yelda KABAKLARLI (AstraZeneca, Satinalma Muduru), Dr. Fatih SARACOGLU (Frentek Otomotiv San. A.S.), Atilla FILIZ     

Group: mailing.openbsd.misc · Group Profile · Search for Gulcin in mailing.openbsd.misc
Author: "Seminer ilan"
Date: Sep 22, 2008 08:30

Hi, Sorry for the above message. C and F are both vectors which dimensions are 90000 now. Later, I will increase the dimension regularly. Thanks. "Gulcin M Muslu" <gulcinmuslu@gmail.com> wrote in message <g6uc9l$clc$1@fred.mathworks.com>... Hi, C and B are both vectors which dimensions are 90000 now. Later, I will increase the dimension regularly.
Show full article (3.94Kb)
Hi, C and B are both vectors which dimensions are 90000 now. Later, I will increase the dimension regularly. Thanks. "Bruno Luong" <b.luong@fogale.findmycountry> wrote in message <g6tsku$5ej$1@fred.mathworks.com>... > "Gulcin M Muslu" <gulcinmuslu@gmail.com> wrote in message > <g6t439$7u9$1@fred.mathworks.com>... > > > > Hi, > > > > In order to solve the coupled     

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Gulcin M Muslu
Date: Aug 1, 2008 00:21

Hi, In order to solve the coupled linear system Ax+ By= C Dx+ Ey= F I tried Titus's suggestion y = (D\E - A\B) \ (D\F-A\C) and John's suggestion, y = [A B ; D E] \ [C F]. Unfortunately, I couldn't get correct results bu using both of them. I get the error message which is ??? Out of memory. Type HELP MEMORY for your options and the warning message Warning
Show full article (1.18Kb) · Show article thread
Hello, Your problem isn't too bad. All you have to do is make your own colormap. You can do this using the following two lines of code gray1=linspace(.3,.7,64)' gray1= [gray1 gray1 gray1] This will make gray1 a new colormap that is not as extreme black or white as the gray colormap. Using Colormap(grey1) will apply your newly created colormap So your new code will be deltax     

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Gulcin M Muslu
Date: Aug 1, 2008 00:00

Hello, Your problem isn't too bad. All you have to do is make your own colormap. You can do this using the following two lines of code gray1=linspace(.3,.7,64)' gray1= [gray1 gray1 gray1] This will make gray1 a new colormap that is not as extreme black or white as the gray colormap. Using Colormap(grey1) will apply your newly created colormap So your new code will be deltax
Show full article (0.84Kb) · Show article thread
Hello, Your problem isn't too bad. All you have to do is make your own colormap. You can do this using the following two lines of code gray1=linspace(.3,.7,64)' gray1= [gray1 gray1 gray1] This will make gray1 a new colormap that is not as extreme black or white as the gray colormap. Using Colormap(grey1) will apply your newly created colormap So your new code will be deltax     

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Gulcin M Muslu
Date: Jul 31, 2008 12:34

"Titus" <titus.edelhofer@mathworks.de> wrote in message <g4lc3e$pc9$1@fred.mathworks.com>... H Gulcin, O.K., first of all, the situation is exactly what all the replyers have anticipated, namely, that solving systems of linear equations is what you are after! Let's see, what we can do. I hope, the dimensions of B and E are somewhat smaller? Whereever you write inv(X
Show full article (3.62Kb) · Show article thread
H Gulcin, O.K., first of all, the situation is exactly what all the replyers have anticipated, namely, that solving systems of linear equations is what you are after! Let's see, what we can do. I hope, the dimensions of B and E are somewhat smaller? Whereever you write inv(X)*Y you should replace by solving the linear system(s) of equations, i.e., use X\Y. Your reformulation of the system     

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Harley
Date: Jul 24, 2008 07:57

"Gulcin M Muslu" <gulcinmuslu@gmail.com> wrote in message <g4latt$9ko$1@fred.mathworks.com>... Dear Titus, I would like to solve linear algebraic system as follows: Ax+ By= C Dx+ Ey= F If I multiply the first eq. by inv(A) and the second eq. by inv(D), then I get the linear system [inv(D)*E-inv(A)*B ] y= [inv(D)*F-inv(A)*C ] So I need
Show full article (1.26Kb) · Show article thread
    

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Harley
Date: Jul 24, 2008 07:55

Show full article (1.26Kb) · Show article thread
    

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Harley
Date: Jul 24, 2008 07:55

Show full article (1.26Kb) · Show article thread
    

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Tim Davis
Date: Jul 5, 2008 07:45

Show full article (2.43Kb) · Show article thread
    

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: Titus
Date: Jul 4, 2008 07:29

Show full article (3.62Kb) · Show article thread
    

Group: comp.softsys.matlab · Group Profile · Search for Gulcin in comp.softsys.matlab
Author: John D'Errico
Date: Jul 4, 2008 07:22

Show full article (1.11Kb) · Show article thread
1 · 2 · next