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found 3 articles for 0.244 sec
Here's two implementations of break, a snappy one from the prelude, and a slow stupid stateful one. They are quickchecked to be identical. Is there a way to prove they are identical mathematically? What are the techniques involved? Or to transform one to the other? import Control.Monad.State import Test.QuickCheck tThis = take 5 . show . mybreak (>4000000) $ [1..10^7] tPrel = take     

Group: fa.haskell · Group Profile · Search for 4000000 in fa.haskell
Author: Thomas Hartman
Date: Jun 7, 2010 11:44

On Jan 28, 7:48 pm, bozak <boz...@gmail.com> wrote: On Jan 28, 8:38 pm, gaogi <gaogi...@gmail.com> wrote: On Jan 27, 8:51 pm, bozak <boz...@gmail.com> wrote: anybody using it... they say it works as good as vonage... $199 and kiss your phone bill good bye... im starting to hear good things about it... the only bad thing is if they go out of business... I have
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On Jan 28, 7:48 pm, bozak <boz...@gmail.com> wrote: > On Jan 28, 8:38 pm, gaogi <gaogi...@gmail.com> wrote: > > > On Jan 27, 8:51 pm, bozak <boz...@gmail.com> wrote: > > > > anybody using it... they say it works as good as vonage... $199 and > > > kiss your phone bill good bye... im starting to hear good things about > > > it... the only bad thing is if they go out of business... > > > I have     

Group: alt.sports.football.pro.sf49ers · Group Profile · Search for 4000000 in alt.sports.football.pro.sf49ers
Author: gaogi
Date: Jan 28, 2010 21:38

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Group: rec.music.hiphop · Group Profile · Search for 4000000 in rec.music.hiphop
Author: gaogi
Date: Jan 28, 2010 21:38

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