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Hi Aaron,
Plot Range is transformed into a machine number. Therefore, 10^-600
changed to zero.
Daniel
Aaron Fude wrote:
> Hi,
>
> I may be wondering why I need this, but I do:
>
> ParametricPlot[{10^-600 z, z}, {z, 0, 100},
> PlotRange -> {{0, 10^-100}, {0, 100}}, AspectRatio -> 1]
>
> works perfectly, but
>
> ParametricPlot[{10^-600 z, z}, {z |
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Group: comp.softsys.math.mathematica · Group Profile · Search for 10000000000000000000 in comp.softsys.math.mathematica
Author: dh
Date: Jul 10, 2008 03:37
Hi, I may be wondering why I need this, but I do: ParametricPlot[{10^-600 z, z}, {z, 0, 100}, PlotRange -> {{0, 10^-100}, {0, 100}}, AspectRatio -> 1] works perfectly, but ParametricPlot[{10^-600 z, z}, {z, 0, 100}, PlotRange -> {{0, 10^-600}, {0, 100}}, AspectRatio -> 1] fails. What gives? Thanks, Aaron The error message is: ParametricPlot::"prng" : "\"Value of option
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