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| found 323 articles for 3.567 sec |
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| On Aug 25, 9:04 pm, carlfo...@comcast.net wrote:
> On Mon, 25 Aug 2008 19:25:38 -0700 (PDT), Frank Krygowski
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> <frkry...@gmail.com> wrote:
> >On Aug 25, 1:35 pm, carlfo...@comcast.net wrote:
> >> On Mon, 25 Aug 2008 07:20:54 -0700 (PDT), Frank Krygowski
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> >> <frkry...@gmail.com> wrote:
> >> >On Aug 25, 3:08 am, carlfo...@comcast.net wrote:
> >> >> On Sun, 24 Aug 2008 15:01:27 -0700 |
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Group: comp.graphics.visualization · Group Profile · Search for 1 10 4 Shear X in comp.graphics.visualization
Author: Eugene Miya
Date: Aug 22, 2006 05:55
On Mon, 25 Aug 2008 19:25:38 -0700 (PDT), Frank Krygowski <frkrygow@gmail.com> wrote: On Aug 25, 1:35 pm, carlfo...@comcast.net wrote: On Mon, 25 Aug 2008 07:20:54 -0700 (PDT), Frank Krygowski <frkry...@gmail.com> wrote: On Aug 25, 3:08 am, carlfo...@comcast.net wrote: On Sun, 24 Aug 2008 15:01:27 -0700 (PDT), Frank Krygowski If you choose to do that
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| Show full article (305.78Kb) |
| On Aug 25, 1:35 pm, carlfo...@comcast.net wrote:
> On Mon, 25 Aug 2008 07:20:54 -0700 (PDT), Frank Krygowski
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>
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> <frkry...@gmail.com> wrote:
> >On Aug 25, 3:08 am, carlfo...@comcast.net wrote:
> >> On Sun, 24 Aug 2008 15:01:27 -0700 (PDT), Frank Krygowski
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> >> >If you choose to do that, rather than "whomping" the fork, you should
> >> >"whomp" an inflated tire mounted on a wheel mounted |
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Group: comp.graphics.visualization · Group Profile · Search for 1 10 4 Shear X in comp.graphics.visualization
Author: Eugene Miya
Date: Aug 8, 2006 05:55
more oddness.... take an image that is 1 inch x 1 inch. Set the container and image origins to 0,0 at 100%%. load the script below. Now move the container around on a 8 x 10 document. As you move beyond the position X=1 inch, the image position becomes negative relative to the container even though what is being input is same as the original. However, when the container is moved vertically
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